# QA – Placement Quizzes | Trigonometry & Height and Distances | Question 7

From a point P on a level ground, the angle of elevation of the top of a tower is 30 degrees. If the tower is 100 m high, the distance of point P from the foot of the tower is:**(A)** 149 m**(B)** 156 m**(C)** 173 m**(D)** 200 m**Answer:** **(C)****Explanation:** Let QR be the tower. Then,

QR = 100 m and angle QPR = 30 degrees.

We know, cot 30° = √3 = PQ/QR.

Therefore, PQ = 100*√3 = 173 m.

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